Challenge Description#

A file named flag.txt.wowok was provided. Its contents looked random/garbled.

Analysis#

Since the flag format is known (SCSC26{...}), the simplest approach is brute-forcing a 1-byte XOR key (0–255) and checking for the substring SCSC26{ in the decoded output.

Exploitation#

Bruteforce found the key 0x32 (50). XOR-ing the file with that key reveals the plaintext flag.

Example 1-liner (Python):

d=open("flag.txt.wowok","rb").read()
print(bytes(b^0x32 for b in d).decode())